Q. A capacitor plates are charged by a battery with ‘V’ volts. After charging battery is disconnected and a dielectric slab with dielectric constant ‘K’ is inserted between its plates, the potential across the plates of a capacitor will become
(i) Zero
(ii) V/2
(iii) V/K
(iv) KV
Answer: (iii) V/K
![](https://www.schoollearners.com/wp-content/uploads/2021/09/image-8.png)
Battery is disconnected
![](https://www.schoollearners.com/wp-content/uploads/2021/09/image-7.png)