Question. Metal M ions form a ccp structure. Oxide ions occupy 1⁄2 octahedral and 1⁄2 tetrahedral voids. What is the formula of the oxide?
Answer: (d) M2O3
Metal M ions form ccp structure. Let number of ions of M be : X
No. of tetrahedral voids = 2x
No. of octahedral voids = x
Number of oxide ions will be 1/2 x + 1⁄2 (2x) = 3/2 x
Formula of oxide = MxO3/2 x = M2O3