On partial hydrolysis, XeF6 gives

Question. On partial hydrolysis, XeF6 gives:
(a) XeO3 +4HF
(b) XeO2F + HF
(c) XeOF4+ H2
(d) XeO2F2 + 4HF

Answer: (d) XeO2F2 + 4HF

XeF4 + H2O -> XeO2F2 + 4HF

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