Three resistors having values R1, R2, and R3 are connected in series to a battery. Suppose R1 carries a current of 2.0 A, R2 has a resistance of 3.0 ohms, and R3

Q. Three resistors having values R1, R2, and R3 are connected in series to a battery. Suppose R1 carries a current of 2.0 A, R2 has a resistance of 3.0 ohms, and R3 dissipates 6.0 watts of power. Then the voltage across R is-
(i) 1V
(ii) 2V
(iii) 3V
(iv) 4V

Answer: (iii) 3V

Given
I = 2 A, R2 = 3 Ω, P3 = 6 W

Power across R3 = V3I
6 W = I2 R3

6/4 = R3 = 3/2 =1.5 Ω

V3 = IR3 = 2 (1.5) = 3 V

error: Content is protected !!